Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.7 - Polynomial and Rational Inequalities - Exercise Set - Page 413: 56

Answer

$(1,2)$

Work Step by Step

Step 1. Rewrite the inequality as $\frac{x}{x-1}-2\gt0$, which gives $\frac{x-2x+2}{x-1}\gt0$, $\frac{-x+2}{x-1}\gt0$, and $\frac{x-2}{x-1}\lt0$ Thus the boundary points are $x=1,2$ Step 2. Using the test points to examine signs across the boundary points, we have $...(+)...(1)...(-)...(2)...(+)...$ Thus the solutions are $1\lt x\lt2$ Step 3. We can express the solutions on a real number line as shown in the figure. Step 4. We can express the solutions in interval notation as $(1,2)$
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