Chapter 2 - Section 2.5 - Zeros of Polynomial Functions - Exercise Set - Page 379: 85

makes sense

This statement makes sense because a solution of $3+\sqrt 5$ means that another solution would be its conjugate, $3-\sqrt 5$. As $x=1$ is also a zero and the coefficients are integers, we can not have the last zero contain a radical, which means that $3+\sqrt 2$ can not be a zero of this function.