Answer
Does not make sense
Work Step by Step
Let $f\left( x \right)={{a}_{n}}{{x}^{n}}+{{a}_{n-1}}{{x}^{n-1}}+\cdot \cdot \cdot +{{a}_{1}}x+{{a}_{0}}$ be a polynomial of degree $n$.
To solve the polynomial for zeros whose degree is greater than two, we do not solve the polynomial equation by using the quadratic equation (because it is only valid for degrees of 2).
For solving the higher degree polynomial, it must be factorized by using synthetic division. After factorization, the zeros of the polynomial are found.
Therefore, this statement does not make sense.
