Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 366: 84

Answer

The value of ${{a}_{n}}=-3$

Work Step by Step

The value $f\left( 3 \right)$ gives the value of the function when $x=3$. $f\left( 3 \right)={{a}_{n}}\left( {{\left( 3 \right)}^{4}}-3\left( {{3}^{2}} \right)-4 \right)$ Now, put $-150$ for $f\left( 3 \right)$ and solve for ${{a}_{n}}$, $\begin{align} & -150={{a}_{n}}\left( 81-3\cdot 9-4 \right) \\ & -150={{a}_{n}}\cdot 50 \\ & {{a}_{n}}=\frac{-150}{50} \\ & {{a}_{n}}=-3 \end{align}$ Thus, the value of ${{a}_{n}}$ is $-3$.
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