Answer
No, the given statement does not make sense.
Work Step by Step
Let us suppose that we have a function $f\left( x \right)={{x}^{2}}-5x+6$ with zeros at $x=2,3$.
Now, finding the solutions of the equation $f\left( x \right)=0$, gives:
$\begin{align}
& {{x}^{2}}-5x+6=0 \\
& {{x}^{2}}-2x-3x+6=0 \\
& x\left( x-2 \right)-3\left( x-2 \right)=0 \\
& \left( x-2 \right)\left( x-3 \right)=0 \\
\end{align}$
And, the value of x is as follows:
$x=2,3$
Thus it is observed that the solution of $f\left( x \right)=0$ give us the zeros of the equation which we already had.
Therefore, the given statement does not make any sense.
