Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Section 2.4 - Dividing Polynomials; Remainder and Factor Theorems - Exercise Set - Page 365: 68

Answer

does not make sense

Work Step by Step

This statement does not make sense because we can also use the Remainder Theorem and synthetic division to obtain the value of a function at a given number.
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