Answer
$4x+2h-1$
Work Step by Step
Step 1. Given $f(x)=2x^2−x−1$, we have
$f(x+h)=2(x+h)^2-(x+h)-1=2x^2+4xh+2h^2-x-h-1$
Step 2. We have:
$f(x+h)-f(x)=4xh+2h^2-h$
Step 3. We have:
$\frac{f(x+h)-f(x)}{h}=\frac{4xh+2h^2-h}{h}=4x+2h-1$
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