Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Cumulative Review Exercises - Page 435: 19

Answer

$32x^2-20x+2$

Work Step by Step

Given $f(x)=2x^2-x-1$ and $g(x)=4x-1$, we have $(f\circ g)(x)=2(4x-1)^2-(4x-1)-1=2(16x^2-8x+1)-4x+1-1=32x^2-16x+2-4x=32x^2-20x+2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.