Answer
$32x^2-20x+2$
Work Step by Step
Given $f(x)=2x^2-x-1$ and $g(x)=4x-1$, we have
$(f\circ g)(x)=2(4x-1)^2-(4x-1)-1=2(16x^2-8x+1)-4x+1-1=32x^2-16x+2-4x=32x^2-20x+2$
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