Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.4 - Introduction to Derrivatives - Exercise Set - Page 1176: 66

Answer

The statement, “Because I have two points to work with, I use the formula for slope, $\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}},$ to find the slope of the tangent line to the graph of a function $\left( a,f\left( a \right) \right)$.” does not make sense.

Work Step by Step

The slope of the tangent line to the graph of a function $y=f\left( x \right)$ at $\left( a,f\left( a \right) \right)$ is given by $\underset{h\to 0}{\mathop{\lim }}\,$ $\frac{f\left( a+h \right)-f\left( a \right)}{h}$, provided that this limit exists. When two points are given, then the line formed is called the secant line and the slope is given by $\frac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}$. At the tangent line, there is only one point of tangency. Also, the slope of the tangent line is evaluated at a single point, so the two points are not necessary to find the tangent line. Thus, the statement does not make sense.
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