Answer
$\frac{1}{6}$
Work Step by Step
Step 1. The probability of rolling an odd number (1,3,5) the first time is $p_1=\frac{3}{6}=\frac{1}{2}$
Step 2. The probability of rolling a number less than 3 (1,2) the second time is $p_2=\frac{2}{6}=\frac{1}{3}$
Step 3. The two events are independent and the probability of rolling an odd number the first time and a number less than 3 the second time is $p=p_1\times p_2=\frac{1}{6}$