Answer
$\frac{1}{36}$
Work Step by Step
Step 1. The probability of rolling a 2 the first time is $p_1=\frac{1}{6}$
Step 2. The probability of rolling a 3 the second time is $p_2=\frac{1}{6}$
Step 3. The two events are independent and the probability of rolling a 2 the first time and a 3 the second time is $p=p_1\times p_2=\frac{1}{36}$
