Answer
$768$
Work Step by Step
The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$
We are given that $ a_1=6, r=2; n=8$
Now, $ a_{8}=6 \times (2)^{8-1}= 6 (2)^7$
$\implies a_8=768$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1073: 9
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