Answer
$-2,12,-72,432,-2592$
Work Step by Step
Here $ a_{n}=-6a_{n-1}$
We are given that $ a_1=-2$
$ a_2=-6a_{2-1} = (-6)(-2)=12 ;\\ a_3=-6a_{3-1} = (-6)(12)=-72 ; \\ a_4= -6a_{4-1} = (-6)(-72)=432; \\ a_5=-6a_{5-1} = (-6)(432)=-2592$
Hence, the first five terms are: $-2,12,-72,432,-2592$