Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Concept and Vocabulary Check - Page 159: 2

Answer

The ${{n}^{th}}$ term of the sequence described in Exercise 1 is given by the formula: ${{a}_{n}}$ = ${{a}_{1}}+\left( n-1 \right)d $, where ${{a}_{1}}$ is the first term and $ d $ is the common difference of the sequence.

Work Step by Step

It is a sequence where after the first term the difference between every term and its preceding term is a constant. The difference between the consecutive terms is called the common difference of the sequence. The initial term of the sequence is ${{a}_{1}}$ and the common difference is d; the nth term can be determined by ${{a}_{n}}={{a}_{1}}+\left( n-1 \right)d $.
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