Answer
$1536$
Work Step by Step
we have $a_1=3 $ and $r=2$
For a geometric sequence $a_n=a_1r^{n-1}$
Thus, $a_n=3(2)^{n-1}$
Now, $a_{10}=3(2)^{10-1}=3(2)^9=1536$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 10 - Mid-Chapter Check Point - Page 1077: 6
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