Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Mid-Chapter Check Point - Page 1077: 5

Answer

78

Work Step by Step

we have $a_1=2 $ and $d=4$ Now, $a_n=a_1+(n-1)d$ Thus, $a_n=2+(n-1)d$ and $a_{20}=2+(20-1)4=2+(19)(4)=78$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.