Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.6 - Transformations of Functions - Exercise Set - Page 245: 151

Answer

The corresponding point is $\left( \left( a+3 \right),b \right)$.

Work Step by Step

Consider the given expression $y=f\left( x-3 \right)$. The graph of the function $y=f\left( x-3 \right)$ is obtained by shifting the graph of the function $f\left( x \right)$ horizontally towards the right. All the x coordinates are shifted to $x+3$. Thus, we will substitute the coordinate $x+3$ in the place of x and the point on the $y$ axis remains the same. Therefore, the point $\left( a,b \right)$ on the graph of $y=f\left( x \right)$ corresponds to a point $\left( \left( a+3 \right),b \right)$ on the graph of the function $y=f\left( x-3 \right)$.
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