Answer
$x=-5/2$, $y=5$, see graph
Work Step by Step
Consider the given linear equation
$6x-3y+15=0$
Use intercepts to graph the given equation in the following manner:
Step 1: Find the $x$ intercept.
To calculate the x intercept of the line, substitute $y=0$ in the given equation and find the value of x
$\begin{align}
& 6x-3\times 0+15=0 \\
& 6x=-15 \\
& x=\frac{\left( -15 \right)}{6} \\
& =-2.5
\end{align}$
So, the $x$ intercept of the equation $6x-3y+15=0$ is $-2.5$. Hence, the line passes through the point $\left( -2.5,0 \right)$.
Step 2: Find the $y$ intercept.
To calculate the y intercept, substitute $x=0$ in the equation and find y.
$\begin{align}
& 6\times 0-3y+15=0 \\
& -3y=-15 \\
& y=\frac{\left( -15 \right)}{\left( -3 \right)} \\
& =5
\end{align}$
So, the $y$ intercept of the equation $6x-3y+15=0$ is 5. Hence, the line passes through the point $\left( 0,5 \right)$.
Step 3: Graph the equation of the straight line.
Locate the two intercepts $\left( -2.5,0 \right)$ and $\left( 0,5 \right)$. Connect them by a straight line.
The graph of the given equation $6x-3y+15=0$ is as follows:
