Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.10 - Modeling with Functions - Exercise Set - Page 293: 24

Answer

The expression for the area of the rectangular field in terms of one of the dimensions of the field x is \[A\left( x \right)=-2{{x}^{2}}+600x\]

Work Step by Step

Let the length of the field be $x$ and breadth of the field be $y$. The amount of fencing required will be equal to the sum of twice the x and y. $2x+y=600$ Calculate $y$ in terms of x. $y=600-2x$ Consider the area of the rectangular field. $A=xy$ Substitute $600-2x$ for y. $A=x\left( 600-2x \right)$ Because A is a function of x, it can be written as, $\begin{align} & A\left( x \right)=x\left( 600-2x \right) \\ & =600x-2{{x}^{2}} \\ & =-2{{x}^{2}}+600x \end{align}$ Hence, the expression for the area of the rectangular field in terms of one of the dimensions of the field x is $A\left( x \right)=-2{{x}^{2}}+600x$
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