Answer
$log_6(3)\approx0.613$
Work Step by Step
Step 1. Let $u=6^x$, we have $u^2-6u+9=0 \longrightarrow (u-3)^2=0 \longrightarrow u=3$
Step 2. For $6^x=3$, we have $x=log_6(3)\approx0.613$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 312: 64
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