Answer
$1$
Work Step by Step
Step 1. Factor the equation to get $(2^x+6)(2^x-2)=0 \longrightarrow 3^x=-6,2$
Step 2. For $2^x=-6$, there is no real solution.
Step 3. For $2^x=2$, we have $x=1$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.6 Logarithmic and Exponential Equations - 5.6 Assess Your Understanding - Page 312: 60
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