Answer
See explanations.
Work Step by Step
Step 1. $f(1)=4(1)^3-2(1)^2-7=-5\lt0$
Step 2. $f(2)=4(2)^3-2(2)^2-7=17\gt0$
Step 3. Based on the Intermediate Value Theorem, the function has a real zero in the given interval.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.4 Logarithmic Functions - 5.4 Assess Your Understanding - Page 298: 141
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