Answer
zeros $x=\pm\frac{1}{2},\pm3$
x-intercepts $x=\pm\frac{1}{2},\pm3$
Work Step by Step
Step 1. Factor and solve the equation $(4x^2-1)(x^2-9)=0$ to get zeros $x=\pm\frac{1}{2},\pm3$
Step 2. We have the x-intercepts $x=\pm\frac{1}{2},\pm3$