Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Chapter Test - Page 796: 5

Answer

\[ \left[\begin{array}{rrr|r} 4&-5&1&0 \\ -2 & -1 & 0 & -25 \\ 1&5&-5&10 \\ \end{array} \right] \]

Work Step by Step

Write the second and third equations in the right form: $-2x-y+6=-19\\-2x-y=-25$ We know that \[ \left\{ \begin{array}{c} a_1x+b_1y+c_1z=d_1 \\ a_2x+b_2y+c_2z=d_2 \\ a_3x+b_3y+c_3z=d_3 \\ \end{array} \right. \] becomes \[ \left[\begin{array}{rrr|r} a_1 & b_1 & c_1 & d_1 \\ a_2 & b_2 & c_2 & d_2 \\ a_3 & b_3 & c_3 & d_3 \\ \end{array} \right] \] Hence here the augmented matrix is: \[ \left[\begin{array}{rrr|r} 4&-5&1&0 \\ -2 & -1 & 0 & -25 \\ 1&5&-5&10 \\ \end{array} \right] \]
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