Answer
See graph
Work Step by Step
We are given the system of inequalities:
$\begin{cases}
x^2+y^2\leq 100\\
4x-3y\geq 0
\end{cases}$
Graph the circle $x^2+y^2=100$. Take a random point (for example, $(-2,0)$) and shade the area that fits the inequality.
Graph the line $4x-3y=0$. Take a random point (for example, $(2,0)$) and shade the area that fits the inequality.
Shade the intersection of the two areas:
