Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 4 - Test - Page 325: 29

Answer

$\frac{76}{21}$

Work Step by Step

$\frac{5+\frac{3}{7}}{2-\frac{1}{2}}$ Multiply the numerator and denominator by 14 to cancel out $\frac{3}{7}$ and $\frac{1}{2}$. $\frac{14(5+\frac{3}{7})}{14(2-\frac{1}{2})}$ = $\frac{14(5)+14(\frac{3}{7})}{14(2)-14(\frac{1}{2})}$ = $\frac{70+6}{28-7}$ = $\frac{76}{21}$
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