Answer
See below:
Work Step by Step
In the given expression:
\[y={{3}^{x}}\]
Substitute the value of x with \[-2,-1,0,1,\text{ and }2\].
\[\begin{align}
& \text{For, }x=-2,y={{3}^{-2}} \\
& \text{For, }x=-1,y={{3}^{-1}} \\
& \text{For, }x=0,y=1 \\
& \text{For, }x=1,y=3 \\
& \text{For, }x=2,y={{3}^{2}} \\
\end{align}\]
Therefore, the ordered pairs are \[\left( -2,{{3}^{-2}} \right),\left( -1,{{3}^{-1}} \right),\left( 0,1 \right),\left( 1,{{3}^{1}} \right),\text{ and }\left( 2,{{3}^{2}} \right)\].
