Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 7 - Algebra: Graphs, Functions, and Linear Systems - Chapter 7 Test - Page 484: 16

Answer

See below:

Work Step by Step

Step I:In the given above expression, replace inequality with equality, \[\begin{align} & 3x-2y=6 \\ & \frac{x}{2}+\frac{y}{\left( -3 \right)}=1 \end{align}\] From the above equation: \[\begin{align} & x-\text{intercept}=\left( \frac{6}{3} \right) \\ & =2 \end{align}\] \[\begin{align} & y-\text{intercept}=\left( \frac{6}{-2} \right) \\ & =-3 \end{align}\] Step II: Put\[x=0,\text{ and }y=0\], in the inequality equation. \[0<6\] It is true. Therefore, the region will be on the side of the origin.
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