Answer
the solution of these linear equations will be \[x=1\], and \[y=-3\].
Work Step by Step
From the first equation, substitute the value of \[x\]in the second given equation.
\[\begin{align}
& 3(y+4)+7y=-18 \\
& 3y+12+7y=-18 \\
& 10y+12=-18 \\
& 10y=-30
\end{align}\]
On solving,\[y=-3\]
Now, back substitute the value of y in first equation.
\[\begin{align}
& x=-3+4 \\
& x=1
\end{align}\]
Therefore, the solution of these linear equations will be \[x=1\], and \[y=-3\].
