Answer
Does not make sense.
Work Step by Step
When a system of linear equation is formed, it can have infinitely many ordered-pair solutions only when graphs of the two coincide, but each equation always has infinitely many ordered-pair solutions.
Consider a system,
\[\left\{ \begin{align}
& 3x+5y=7 \\
& 3x-y=1 \\
\end{align} \right.\]
There are two linear equations. Subtract one equation from the other.
\[\begin{align}
& \left( 3x+5y \right)-\left( 3x-y \right)=7-1 \\
& 3x+5y-3x+y=6 \\
& 6y=6 \\
& y=1
\end{align}\]
Now put the value of y in first equation.
\[\begin{align}
& 3x+5y=7 \\
& 3x+5\left( 1 \right)=7 \\
& 3x=7-5 \\
& x=\frac{2}{3}
\end{align}\]
So, the above system of linear equation has unique solution, that is, \[\left\{ \frac{2}{3},1 \right\}\].
Consider another system,
\[\left\{ \begin{align}
& 3x+6y=12 \\
& x+2y=4 \\
\end{align} \right.\]
Multiply the second equation by 3
\[\begin{align}
& 3\left( x+2y \right)=3\left( 4 \right) \\
& 3x+6y=12
\end{align}\]
Both the equations are same, so the above system of linear equations has infinitely many ordered-pair.
Hence, every system of linear equations may have infinitely many ordered-pair solutions, but not always as an equation.
