Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter Summary, Review, and Test - Review Exercises - Page 404: 29

Answer

\[B=2A-C\]

Work Step by Step

An expression can be solved for a variable by performing various mathematical operations to isolate a specified variable on one side of the expression. The equation can be solved for \[B\] as follows: \[A=\frac{B+C}{2}\] Multiply both sides of the expression by \[2\]. This gives, \[\begin{align} & 2A=2\times \frac{B+C}{2} \\ & 2A=B+C \\ \end{align}\] Subtract \[C\] from both sides of the expression which gives, \[\begin{align} & 2A-C=B+C-C \\ & 2A-C=B \\ \end{align}\]
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