Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter Summary, Review, and Test - Review Exercises - Page 404: 22

Answer

The body count in scream, scream-2 and scream-3 are \[6\],\[8\]and \[9\].

Work Step by Step

Consider that the body count in the scream is \[\left( x \right)\]. The total body count is \[33\]in all scream. The body count in scream is \[x\], in scream-2 is \[\left( x+2 \right)\]and in scream-3 is \[\left( x+3 \right)\]and it is provided that the body count in scream-4 is \[10\]. \[\text{scream}+\text{scream-2}+\text{scream-3}+\text{scream-4}=33\] Now, substitute the values, \[\begin{align} & x+\left( x+2 \right)+\left( x+3 \right)+10=33 \\ & 3x+15=33 \\ & 3x=18 \\ & x=6 \\ \end{align}\] Since, the value of\[x\]is \[6\]. Therefore, the body count in scream is \[6\]. Now, find the body count in the scream-2 and scream-3 by substituting the value of \[\left( x \right)\]. The body count in scream-2 is \[8\]and the body count in the scream-3 is \[9\]. Hence, the body count in scream, scream-2 and scream-3 are \[6\],\[8\]and \[9\].
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