Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - Chapter 6 Test - Page 406: 13

Answer

7 years

Work Step by Step

Let us consider the value of time (in years) be that takes for a new car value to reach \[\$12,250\], then the variation in the car value due the decreasing value of the car per year can algebraically be stated as, \[\begin{align} & \$50,750-\left(\$5500\right)t=\$12,250\\&\left(5500\right)t=50,750-12,250\\&5500t=38,500\\&t=7\end{align}\] It would take 7 years for new car value worth \[\$50,750\], with a decreasing value of \[\$5500\] to reach a value of \[\$12,250\].
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