Answer
$y=27$.
Work Step by Step
After multiplying both sides by $(y-5)(y+6)$: $2(y+6)=3(y-5)\\2y+12=3y-15\\y=27$.
Check: $\frac{2}{27-5}=\frac{1}{11}=\frac{3}{27+6}$, thus it is a good solution.
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 362: 72
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