Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.2 Linear Equations in One Variable and Proportions - Exercise Set 6.2 - Page 362: 11

Answer

{$\frac{-1}{4}$}

Work Step by Step

-8x = 2 Step 1: Divide both the sides by -8 $\frac{-8x}{8}$ = $\frac{2}{-8}$ Step 2: Simplify x= $\frac{-1}{4}$ Now we check the proposed solution, $\frac{-1}{4}$, by replacing x with $\frac{-1}{4}$ in the original equation. Step 1: the original equation -8x = 2 Step2: Substitute $\frac{-1}{4}$ for x -8.($\frac{-1}{4}$) = 2 Step 3: Solve -8. ($\frac{-1}{4}$) = 2 2=2 Since the check results in true statement, we conclude that the solution set of the given equation is {$\frac{-1}{4}$}
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