Answer
$10+2\sqrt5$
Work Step by Step
The distributive property states that for any real numbers $a, b, $ and $c$,
$a(b+c) =a\cdot b+a \cdot c$
Thus, apply the distributive property to the given problem to find:
$=\sqrt{10} \cdot \sqrt2 + \sqrt{10} \cdot \sqrt{10}
\\=\sqrt{20}+10
\\=\sqrt{4(5)} + 10
\\=2\sqrt{5}+10$
