Answer
$6+2\sqrt3$
Work Step by Step
The distributive property states that for any real numbers $a, b, $ and $c$,
$a(b+c) =a\cdot b+a \cdot c$
Thus, apply the distributive property to the given problem to find:
$=\sqrt{6 \cdot 2} + \sqrt6 \cdot \sqrt{6}
\\=\sqrt{12}+6
\\=\sqrt{4(3)} + 6
\\=2\sqrt{3}+6$