Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.1 Number Theory: Prime and Composite Numbers - Exercise Set 5.1 - Page 258: 121

Answer

The given number is divisible by $9$.

Work Step by Step

A number is divisible by $9$ if the sum of all its digits is divisible by $9$. The sum of the digits of the given number is: $=4+8+2+0+1+6+5+1 \\=27$ Note that $27$ is divisible by $9$ since $9(3) = 27$. Thus, the given number is divisible by $9$.
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