Answer
$d=7$
Work Step by Step
A number is divisible by 9 if the sum of its digits is a multiple of 9.
Add the digits of the number to obtain:
$=2+3+4+2+d
\\=11+d$
Since $0 \le d \le 9$, the only possible value of $11+d$ that is a multiple of 9 is 18.
Thus, $d$ must be 7.