Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.1 Number Theory: Prime and Composite Numbers - Exercise Set 5.1 - Page 256: 5

Answer

The number 26428 is divisible by: 2 and 4. It is not divisible by 3, 5, 6, 8, 9, 10 or 12.

Work Step by Step

Using divisibility rules, we can find that 26428 is divisible by: a. 2 --Yes. It is even. Its ones digit is either a 0, 2, 4, 6, or 8. b. 3 --No. The sum of its digits (2 + 6 + 4 + 2 + 8 = 22) is not divisible by 3. c. 4 --Yes. The last 2 digits (28) make a number that is divisible by 4. d. 5 -- No. The ones digit is not a zero, nor is it a five. e. 6 --No. It is not divisible by both 2 and 3. f. 8 -- No. The last three digits (428) make a number that is not divisible by 8. g. 9 -- no. The sum of its digits (22) is not divisible by 9. h. 10 -- no. Its ones digit is not a zero. i. 12 --no. It is not divisible by both 3 and 4.
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