Answer
The given statement is "{3,7,9} ⊆ {9,7,3,1}" False.
Work Step by Step
{3,7,9} ⊆ {9,7,3,1}
From the given question,
the element of the first are present in the second set and they have different number of elements, So first set is a proper subset of the second set. ({3,7,9} ⊂ {9,7,3,1})
The given statement is "{3,7,9} ⊆ {9,7,3,1}" False.
