Answer
The given statement is "{e,f,g} ⊂ {d,e,f,g,h,i}" True.
Work Step by Step
{e,f,g} ⊂ {d,e,f,g,h,i}
From the given question,
the element of the first are present in the second set but the reverse is not true. So first set is a proper subset of the second set.
The given statement is "{e,f,g} ⊂ {d,e,f,g,h,i}" True.
