Answer
False
Work Step by Step
Set\[A\cup \varnothing \]contains all those elements which are present either in set A or set\[\varnothing \]or in both. Now, as there is no element in set\[\varnothing \].
So,
\[A\cup \varnothing =A\]
Therefore, the statement ‘\[A\cup \varnothing =\varnothing \]’ is false.
The true statement is:\[A\cup \varnothing =A\]