Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.3 Venn Diagrams and Set Operations - Exercise Set 2.3 - Page 83: 161

Answer

False

Work Step by Step

Set\[A\cup \varnothing \]contains all those elements which are present either in set A or set\[\varnothing \]or in both. Now, as there is no element in set\[\varnothing \]. So, \[A\cup \varnothing =A\] Therefore, the statement ‘\[A\cup \varnothing =\varnothing \]’ is false. The true statement is:\[A\cup \varnothing =A\]
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