Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.3 Venn Diagrams and Set Operations - Exercise Set 2.3 - Page 83: 158

Answer

$(A \cup B) \subseteq A$ $\text{The statement is false}$ $ Because (A \cup B) \text { contains the elements of } A \text { and also the elements of } B .$ $\therefore (A \cup B) \text { never become a subset of}$ $A$ --- $\text{to make the statement true we make a necessary change(s) as follow:}$ $A \subseteq(A \cup B)$ $\text{the above statement always be true because (A) always become a subset}$ $\text{of }$$ (A \cup B)$

Work Step by Step

$(A \cup B) \subseteq A$ $\text{The statement is false}$ $ Because (A \cup B) \text { contains the elements of } A \text { and also the elements of } B .$ $\therefore (A \cup B) \text { never become a subset of}$ $A$ --- $\text{to make the statement true we make a necessary change(s) as follow:}$ $A \subseteq(A \cup B)$ $\text{the above statement always be true because (A) always become a subset}$ $\text{of }$$ (A \cup B)$
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