Answer
$A$$_{laptop}$ = 96 in $^2$
$A$$_{notebook}$ = 77 in $^2$
$A$$_{dif}$ = 19 in $^2$
Work Step by Step
To determine the difference in the areas we must determine each area and then subtract the smallest from the largest.
The laptop screen is 12.3 in. x 7.8 in. Therefore:
$A$$_{1}$ = 12.3 in x 7.8 in
$A$$_{1}$ = 95.94 in
$A$$_{1}$(To the nearest whole number) = 96 in $^2$
The notebooks screen is 10.3 in. x 7.5 in. Therefore:
$A$$_{2}$ = 10.3 in x 7.5 in
$A$$_{2}$ = 77.25 in
$A$$_{2}$(To the nearest whole number) = 77 in $^2$
Therefore, the difference in area is $A$$_{1}$ - $A$$_{2}$.
$A$$_{dif}$ = 96 in - 77 in
$A$$_{dif}$ = 19 in $^2$
