Basic College Mathematics (9th Edition)

Published by Pearson
ISBN 10: 0321825535
ISBN 13: 978-0-32182-553-7

Chapter 8 - Geometry - 8.3 Rectangles and Squares - 8.3 Exercises - Page 553: 20

Answer

The perimeter of a regulation volleyball court is $54m$ The area of a regulation volleyball court is $162m^{2}$

Work Step by Step

Let $P = $ perimeter of volleyball court $P = 2(18) + 2(9)$ $P = 36 + 18$ $P = 54m$ Let $A = $ area of volleyball court $A = length \times width$ $A = 18 \times 9$ $A = 162m^{2}$ Refer to Figure1.
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