Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapters 1-3 - Adding and Subtracting Fractions - Cumulative Review - Page 262: 24

Answer

$13\frac{1}{2}$

Work Step by Step

$9\div\frac{2}{3}$ = $9\times\frac{3}{2}$ (division of factors i.e. multiply by the reciprocal of the second factor) = $\frac{9\times3}{2}$ = $\frac{27}{2}$ = $13\frac{1}{2}$
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