Answer
$\frac{9}{10}$
Work Step by Step
$\frac{3}{4}\div(\frac{1}{3}+\frac{1}{2})$
(First solve Bracket)
= $\frac{3}{4}\div(\frac{1\times2}{3\times2}+\frac{1\times3}{2\times3})$ (LCM of 3 & 2 is 6)
= $\frac{3}{4}\div(\frac{2}{6}+\frac{3}{6})$
= $\frac{3}{4}\div(\frac{2+3}{6})$ (addition of fractions with same denomiator)
= $\frac{3}{4}\div(\frac{5}{6})$
= $\frac{3}{4}\div\frac{5}{6}$
= $\frac{3}{4}\times\frac{6}{5}$
= $\frac{3}{2}\times\frac{3}{5}$
= $\frac{9}{10}$
