Answer
$\frac{11}{27}$
Work Step by Step
$(\frac{2}{3})^{3}+(\frac{2}{3}-\frac{5}{9})$
= $(\frac{2}{3}\times\frac{2}{3}\times\frac{2}{3})+(\frac{2}{3}-\frac{5}{9})$ (First solve bracket)
= $(\frac{2\times2\times2}{3\times3\times3})+(\frac{2\times3}{3\times3}-\frac{5}{9})$
(least common multiple of 3 &9 is 9)
= $\frac{8}{27}+(\frac{6}{9}-\frac{5}{9})$
= $\frac{8}{27}+(\frac{6-5}{9})$ (subtract numerators)
= $\frac{8}{27}+(\frac{1}{9})$
= $\frac{8}{27}+(\frac{1\times3}{9\times3})$
(least common multiple of 9 &27 is 27)
= $\frac{8}{27}+(\frac{3}{27})$
= $\frac{8+3}{27}$
= $\frac{11}{27}$
