Answer
$\frac{1}{2}$
Work Step by Step
$\frac{3}{8}\div(\frac{1}{2}+\frac{1}{4})$
= $\frac{3}{8}\div(\frac{1}{2}+\frac{1}{4})$ (First solve bracket)
= $\frac{3}{8}\div(\frac{1\times2}{2\times2}+\frac{1}{4})$
(least common multiple of 2 &4 is 4)
= $\frac{3}{8}\div(\frac{2}{4}+\frac{1}{4})$
= $\frac{3}{8}\div(\frac{2+1}{4})$ (add numerators)
= $\frac{3}{8}\div(\frac{3}{4})$
= $\frac{3}{8}\times(\frac{4}{3})$ (reciprocal)
= $\frac{1}{2}$
